7(4x^3/12x^4)^0

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Solution for 7(4x^3/12x^4)^0 equation:


D( x )

((4*x^3)/12)*x^4 = 0

((4*x^3)/12)*x^4 = 0

((4*x^3)/12)*x^4 = 0

1/3*x^7 = 0 // : 1/3

x^7 = 0

x = 0

x in (-oo:0) U (0:+oo)

7*(((4*x^3)/12)*x^4)^0 = 0

7 = 0

(((4*x^3)/12)*x^4)^0 = 0

1 = 0

(((4*x^3)/12)*x^4)^0 = 0

1 = 0

x belongs to the empty set

7*(((4*x^3)/12)*x^4)^0 = 0 <=> 7 = 0 or 7*(((4*x^3)/12)*x^4)^0 = 0 <=> (((4*x^3)/12)*x^4)^0 = 0

x belongs to the empty set

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